Re: gcc builtin memcpy is bogus?

From: Andreas Schwab <schwab_at_suse.de>
Date: 2003-12-09 03:25:27
Matthew Wilcox <willy@debian.org> writes:

> This is a fun one ... I don't know what to blame for this.
>
> struct rfd {
>         u16 status;
>         u16 command;
>         u32 link;
>         u32 rbd;
>         u16 actual_size;
>         u16 size;
> };
>
> static void e100_rx_rfa_add_tail(struct nic *nic, struct rx_list *curr)
> {
>         struct rfd *rfd = (struct rfd *)curr->skb->data;
>         
>         memcpy(rfd, &nic->blank_rfd, sizeof(struct rfd));
> }
>
> I'm using gcc (GCC) 3.3.2 (Debian) for this.
>
> The kernel doesn't use -fno-builtin or -fno-builtin-memcpy so it attempts
> to optimise this by doing 4-byte loads and stores.  Problem is, the
> destination is misaligned (deliberately), so the kernel emits unaligned
> messages.  Adding -fno-builtin to the command line turns this back into
> a call to memcpy.
>
> So how should this be fixed?
>
>  - Improve gcc's builtin memcpy to work on non-aligned structs (unlikely)?

The builtin memcpy is correct, casting unaligned data is invoking
undefined behaviour here.

>  - Somehow tag the pointer or the struct that it's unaligned?
>  - Compile with -fno-builtin-memcpy (and probably a few others too)?
>
> Other suggestions?

- Don't use the casted address, but rather the original pointer in the
  memcpy call.

Andreas.

-- 
Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux AG, Maxfeldstraße 5, 90409 Nürnberg, Germany
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"And now for something completely different."
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Received on Mon Dec 8 11:26:15 2003

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