Thanks for clarifying. Chandra --- David Mosberger <davidm@napali.hpl.hp.com> wrote: > Hi Chandra, > > >>>>> On Fri, 4 Apr 2003 09:50:16 -0800 (PST), > Chandra Kapate <cs_kapate@yahoo.com> said: > > Chandra> Hi, > Chandra> I was looking at how execve syscalls work > wrt to 32/64 > Chandra> syscalls. I have a basic question. I > appreciate if > Chandra> some once can clarify. I apologize if I > am overlooking > Chandra> some thing very obvious. > > Chandra> The ia32_execve (in ia32_entry.S) sets up > out0, out1, > Chandra> out2 and out3 before invoking > sys32_execve. The out3 > Chandra> is setup for regs. But, in sys32_execve, > the regs > Chandra> is set locally using 9th parameters. I > can see how > Chandra> the regs is set using 9th parameter. I > don't > Chandra> understand why is set again in > sys32_execve > Chandra> when it is already set in out3 in > ia32_execve and > Chandra> could have used as 4th parameter? Does > args mis-match > Chandra> between ia32_execve and sys32_execve > matter? > Chandra> OTH, sys_execve does use the regs set in > ia64_execve. > Chandra> Sorry, if i am overlooking something. > > Looks like you found an inconsistency. The code > should work as it > stands, but it certainly looks confusing. It looks > to me like one end > of the interface was updated at one point but not > the other. > > The reason sys32_execve() works is because the 9th > (scalar) argument > is the first argument that gets passed on the stack. > Taking its > address will give "sp+16", which is exactly what > out3 is set to. > > Thanks for pointing out this inconsistency (I'll see > about fixing it). > > --david __________________________________________________ Do you Yahoo!? Yahoo! Tax Center - File online, calculators, forms, and more http://tax.yahoo.comReceived on Tue Apr 08 06:28:59 2003
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